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Image Capture Library is an open source library which enables developers to build software solutions for image capture and interpretation.Q:

How do I figure out if a set is an ideal?

I want to figure out if the following set is an ideal.
$\{(x,y)\in \mathbb{R}^2 \mid x^2 + y^2 \le 1\}$
I know that if I were to find a contradiction, that would be a good start. Since we can always make $x$ or $y$ infinite or negative, I tried looking for a contradiction, like by saying:
$x \to -\infty$
$y \to \infty$
But there are no $x$ or $y$ in the set, so we can’t have an infinite value. So is this set an ideal?

A:

The short answer is yes, because it is the zero ideal.

The zero ideal is the ideal containing the zero element.
If $R$ is a ring and $I$ is an ideal of $R$ and $a\in R$ (a ring element) then we say that $a$ is in $I$ if and only if there exists a $b\in I$ such that $b=a$. The zero ideal is the ideal containing the zero element.
In the case of $R=\mathbb{R}$ and $I=\{( 384a16bd22

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